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What is the chance of Pollard being done????

 

The probability of Pollard being done in probability theory is denoted by the notation P(event). The probability of any event is the number of times that event can occur divided by the total number of possible outcomes. Probabilities can be expressed as fractions or decimals. The total probability of all possible outcomes always sums to one (1). Thus, the probability of getting a head on the flip of a balanced coin, P(head) = ½ = 0.5 because 2 outcomes (heads or tails) are equally possible when a balanced coin is flipped. If there is an equal probability of Alice, Ben, Charlie or Danièle being the driver of Danièle's motorcycle, then the probability of Ben being the driver can be denoted P(Ben) = ¼ = 0.25.

 

Again, the probability of Pollard being done is usually a number between 0 and 1. If the probability of an event is 0, then the event is impossible -- such as rolling a seven with a single die ("one dice"). If the probability of an event is 1, then the event is certain -- such as the probability of getting a head or tail with a coin that will not stand on its edge. The probability of an event is calculated as:

 

Number of outcomes resulting in the event

P(Event) = -------------------------------------------

Total number of possible outcomes

 

Thus, the probability of rolling a number greater than 4 with a single die will be:

 

P(5,6) 2 1

---------------- = --- = --- = 0.33333....

P(1,2,3,4,5,6) 6 3

 

So the probability of Pollard being done is P x the probable eventuality of the total sum fractional decimal.

 

 

 

i'd try and pick up V.Davis...or Heller

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The probability of Pollard being done in probability theory is denoted by the notation P(event). The probability of any event is the number of times that event can occur divided by the total number of possible outcomes. Probabilities can be expressed as fractions or decimals. The total probability of all possible outcomes always sums to one (1). Thus, the probability of getting a head on the flip of a balanced coin, P(head) = ½ = 0.5 because 2 outcomes (heads or tails) are equally possible when a balanced coin is flipped. If there is an equal probability of Alice, Ben, Charlie or Danièle being the driver of Danièle's motorcycle, then the probability of Ben being the driver can be denoted P(Ben) = ¼ = 0.25.

 

Again, the probability of Pollard being done is usually a number between 0 and 1. If the probability of an event is 0, then the event is impossible -- such as rolling a seven with a single die ("one dice"). If the probability of an event is 1, then the event is certain -- such as the probability of getting a head or tail with a coin that will not stand on its edge. The probability of an event is calculated as:

 

Number of outcomes resulting in the event

P(Event) = -------------------------------------------

Total number of possible outcomes

 

Thus, the probability of rolling a number greater than 4 with a single die will be:

 

P(5,6) 2 1

---------------- = --- = --- = 0.33333....

P(1,2,3,4,5,6) 6 3

 

So the probability of Pollard being done is P x the probable eventuality of the total sum fractional decimal.

 

 

 

i'd try and pick up V.Davis...or Heller

 

This post just made this thread very hard to de-throne as being the most useless and worst thread ever.

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